Solve the following equation algebraically: -16 = 16x?
How many solutions does this equation have? Explain.
a. -1 = x3; One solution because only -1 will satisfy the equation.
b. -1 = x2; No real solution because there is no real number that, when squared, produces -1.
c. 1= x?: Two solutions because the square root of 1 is positive 1 and negative 1.
d. 1=-x?: One solution because only -1 will satisfy the equation.