What must be true about segment MN?

The true properties of segment MN are;

1) MN is parallel to CB

2) MN = 2

Step-by-step explanation:

From the figure, we have;

The length of segment AN = 1

The length of segment NC = 2 = 2 × The length of segment AN

The length of segment AM = 1.8

The length of segment MB = 3.6 = 2 × The length of segment AM

The length of segment AC = 1 + 2 = 3

The length of segment AB = 1.8 + 3.6 = 5.4

Therefore, the length of transversal segments AC and AB are proportionally cut by the two lines, MN and CB

By the triangle proportionality theorem, two transversals are proportionally divided when they are crossed by two or more parallel lines

1) Therefore, lines MN and CB are parallel lines

Whereby we have that MN CB, we get;

ΔAMN ~ ΔABC

Therefore;

AN/AC = MN/CB

Plugging in the values, we get;

1/3 = MN/6

NM = 6 × 1/3 = 2

2) MN = 2

The length of segment CB = 6

Therefore, what must about segment MN are;

MN is parallel to CB and MN = 2.

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629