How long (in years) would $900 have to be invested at 11.3%, compounded continuously, to earn $500 interest? (Round your answer to the nearest whole number.)

6.13 years

Step-by-step explanation:

The computation of the number of years is shown below:

As we know that

Amount = Principal ×e^{rate,time period}

($900 +  $500)  = $700 × e^{11.3%, time period}

$1,400 = $700 × e^{11.3%, time period}

ln(2) = 0.113× time period

0.693147181 ÷ 11.3 = time period

= 6.13 years

it reflected because of the glass maube

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.