If the total area of the rectangle below is 168 square units, how long is each side? To find out how long the x side must be, use the diagram below to complete the table and answer the questions that follow. Also if you can, answer the question at the bottom of my image! I'd appreciate the help.

For a rectangle of length L and width W, the area is:

A = L*W

In this case we have:

L = x + 2

w = x

Then the area of this rectangle is:

A = (x + 2)*x = x^2 + 2*x

And we know that this area is equal to 168 square units, then:

168 = x^2 + 2*x

We can rewrite this as:

x^2 + 2*x - 168 = 0

This is a quadratic equation, and the solutions are given by Bhaskara's equation, such that for an equation of the form:

a*x^2 + b*x + c = 0

The solutions are given by:

In our case, the solutions are:

Then the two solutions are:

x = (2 - 26)/2 = -12

x = (2 + 26)/2 = 14

Notice that x is the width of the rectangle, and we can not have a negative width, so we can discard the first option.

Then we can conclude that:

x = 14

Then the width of the rectangle is 14 units long, and the length is 14 + 2 = 16 units long.

Now, how the lengths are related to eachother?

The length is 2 units longer than the width.

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>