Q5 Q31.) Use the Pythagorean Theorem to find the length of the missing side of the right triangle. Then find the value of each of the six trigonometric functions of theta.

See answers in bold below

Step-by-step explanation:

Using pythagoras theorem to find the unknown side a;

c² = a²+b²

a² = c²-b²

a² = 20²-16²

a² = 400 -256

a² = 144

a = √144

a = 12

for the six trigonometry functions;

According to SOH CAH TOA

sin theta = opposite/hypotenuse

Opposite = 12

Hypotenuse = 20

sin theta = 12/20

sin theta = 3/5

cos theta = adj/hyp

cos theta = 16/20

cos theta = 4/5

tan theta = opp/adj

tan theta = 12/16

tan theta = 3/4

cosec theta = 1/sintheta

cosec theta = 1/(3/5)

cosec theta = 5/3

sec theta = 1/cos theta

sec theta = 1/(4/5)

sec theta = 5/4

answer: i can’t tell you that

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)