The following table shows the times of trains between Juno and Odiham. Station
Times
Station
Times
Juno
07:15
22:15
Odiham
07:00
22:00
Kepler
07:24
and every
22:24
Ninar
07:10
and every
22:10
Lemma
07:32
20 minutes 22:32
Morgan
07:25
20 minutes 22:25
07:40
until
22:40
Lemma
07:33
until
22:33
Morgan
Ninar
07:55
22:55
Kepler
07:41
22:41
Odiham
08:05
23:05
Juno
07:50
22:50
Ferdo lives in Juno. He has a business appointment in Odiham and needs to be there for at least
two hours between his arrival in and departure from Odiham. He leaves Juno on the first train after
08:30.
(a) What is the earliest time that Ferdo can be back at Juno station after his appointment?

(a) The earliest time that Ferdo can be back at Juno station is 12:15

Step-by-step explanation:

From the given table, we have;

The starting time for train departure from Juno = 07:15

The frequency of train departures from Juno = Every 20 minutes

The time of departure, 't₁' of first train that departs from Juno after 08:30 is given as follows;

The train departure times from Juno = 07:15, 07:35, 07:55, 08:15, 08:35

Therefore;

The time at which the first train departs from Juno after 08:30 = 08:35

The time it takes a train to travel from Juno to Odiham = 0:805 - 07:15 = 50 minutes

The time of arrival of the train Ferdo takes from Juno at Odiham = 08:35 + 50 minutes = 09:25

The number of hours Ferdo spends at Odiham = 2 hours

The time after which Ferdo departs from Odiham = 09:25 + 02:00 = 11:25

The time of departure of the train from Odiham after 11:25 = 08:05 + 20 minutes × 10

Therefore, the time of departure of the train from Odiham after = 11:25

The time it takes on the trip back to Juno from Odiham = 50 minutes

The earliest time that Ferdo can be back at Juno station = 11:25 + 50 minutes = 12:15

answer: y=4000x+14000

step-by-step explanation: