At a teddy bear workshop, customers can select from black, brown, gold, white, blue, or pink for their bear's colors. If a father randomly selects two bear colors, what is the probability that he will select a white bear for his son and a pink bear for his daughter? The father cannot pick the same color for both bears.

Step-by-step explanation:

Given

Colors: Black, Brown, Gold, White, Blue, Pink

Required

P(White and Pink)

Since the father can not select the same color, then it is a selection without replacement.

So, we have:

This gives:

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation