Does the following scenario describe a dependent or independent sequence of events: Flipping a coin and getting a "heads" and then flipping a second coin and getting a "heads".

I hope this helps <3

Step-by-step explanation:

What's the probability of getting heads on the second toss given that the first toss was a head. (Trying to refresh my probability a bit). I've seen this analyzed like this:

HH 1/4

HT 1/4

TH 1/4

TT 1/4

So since we are given information (Head on first flip), then TT goes away and were are left with:

HH 1/3

HT 1/3

TH 1/3

So we could say that HH now has a 1/3 probability. Should we not also get rid of TH, since we know that the first flip is a head? So now we have:

HH 1/2

HT 1/2

3 1/3 x 2 3/5 = 8 2/3

step-by-step explanation:

just multiply the first number by the second number to get your answer.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb