Please help! What is the justification that C’ = F in step 2.
A) C’ and F are the same distance from E along the same ray.
B) Both C’ and F lie on intersection points of circles centered at D and E with radii DF and EF, respectively. There are two such possible points, one on each side of DE.
C) C’ and F are at the intersection of the same pair of rays

i believe the answer is the polygon, heptagon.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.