The frequency table shows the data from a random survey of students that asked how they earn money during the summer.
Student Summer Work
Babysit
Do Not
Babysit
Total
Do Yard
Work
6
9
15
Do Not
Do Yard
Work
12
8
20
Total
18
17
35
A. What fraction of the students surveyed babysit?
B. What is the relative frequency of students who babysit and do yard work compared to all who do yard work?
Enter the answer as a fraction or decimal.

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

cutt.ly/XzW3SUN

-18

step-by-step explanation:

because mean value defines that total sum value over total number of set

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!