ASAP! Please answer this ASAP! THANK YOU! Let f(x) = 18/1+3e^-0.1x What is the point of maximum growth rate for the logistic function f(x)? Show all work. Round your answer to the nearest hundredth.

(0, 4.5)

Step-by-step explanation:

f(x)=c/1+Ae^-Bx

Y=C

C=18      A=3      -B=-0.1

*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*

f(0)=18/1+3e^-o.1(0)

= 18/1+3e^0

=18/1+3(1)

=18/1+3

=18/4

=4.5

x=0    y=4.5

Maximum growth rate = (x,y) --> (0, 4.5)

Hope this helps:))!!

f(x)=c/1+Ae^-Bx

Y=C

C=18      A=3      -B=-0.1

*Replace x with 0 in the equation, so you know 0 is the x value, and it leads you to the y value*

f(0)=18/1+3e^-o.1(0)

= 18/1+3e^0

=18/1+3(1)

=18/1+3

=18/4

=4.5

x=0    y=4.5

Maximum growth rate = (x,y) --> (0, 4.5)

Hope this helps:))!!

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐