A man on a 135-ft vertical cliff looks down at an angle of 16°13' and sees his friend. a) How far away is the man from his friend?

b) How far is the friend from the base of the cliff?

A) Use the trigonometric function and ratio cos(x) = A/H. (Adjacent/Hypotenuse)
1. cos(x) = 135/H
2. H*cos(16°) = 135
3. H = 135/cos(16°)
***Make sure calculator is in degree mode***
4. H = 140.44 ft (rounded to two decimal places)


b) Use the function and ratio tan(x) = O/A (Opposite/Adjacent)
1. tan(x) = O/A
2. tan(16°) = O/135
3. 135*tan(16°) = O
4. O = 38.71 ft (two decimal places)

Good luck!