In ΔABC, the measure of ∠C=90°, the measure of ∠A=39°, and BC = 9.7 feet. Find the length of AB to the nearest tenth of a foot. (please answer correctly I will give brainliest)

15.4 ft

Step-by-step explanation:

\sin A = \frac{\text{opposite}}{\text{hypotenuse}}=\frac{9.7}{x}

sinA=

hypotenuse

opposite

​

=

x

9.7

​

\sin 39=\frac{9.7}{x}

sin39=

x

9.7

​

x\sin 39=9.7

xsin39=9.7

Cross multiply.

\frac{x\sin 39}{\sin 39}=\frac{9.7}{\sin 39}

sin39

xsin39

​

=

sin39

9.7

​

Divide each side by sin 39.

x=\frac{9.7}{\sin 39}=15.4135\approx 15.4\text{ feet}

x=

sin39

9.7

​

=15.4135≈15.4 feet

Type into calculator and round to the nearest tenth of a foot.

answer: i'm great at algebra

~coco

step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.