Find the vertices and foci of the hyperbola with equation quantity x plus 1 squared divided by 225 minus the quantity of y plus 5 squared divided by 400 = 1. a. Vertices: (19, -5), (-21, -5); Foci: (-21, -5), (19, -5)
b. Vertices: (14, -5), (-16, -5); Foci: (-26, -5), (24, -5)
c. Vertices: (-5, 14), (-5, -16); Foci: (-5, -26), (-5, 24)
d. Vertices: (-5, 19), (-5, -21); Foci: (-5, -21), (-5, 19)

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

triangle and cube

step-by-step explanation:

c.

step-by-step explanation:

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: