Given the equation 2x^2 + 12x + 4 = 0, what are the zeros of the equation? O x=-6, -3 O No Real Solutions O x=-5.6,-0.4 O x = 0.4, 5.6 O x= 3,6​

the square root of what number? if you add that, then someone will probably answer the question.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.