Natalia bought 4 boxes of pencils and 9 reams of paper for 75$. Ronnie by eight boxes of pencils and five reams of paper for 67.

a box of pencil cost=$4.395

And a ream of paper cost=$6.38

Step-by-step explanation:

Let the cost of box of pencil be represented as p

And the cost of ream of paper be represented as r

Such that

4 boxes of pencils and 9 reams of paper costing 75$ be represented as

4p+9r=75equation 1

Also, eight boxes of pencils and five reams of paper for 67 be represented as

8p + 5r=67equation 2

Solving

4p+9r=75equation 1

8p + 5r=67equation 2

By elimination method, multiply equation 1 by 2 and equation 2 by 1

8p +18r=150---equation 3

8p+5r=67equation 4

Subtracting equation 4 from equation 3

13r=83

r=83/13

r=6.38

Putting the value of r=6.38 in equation 1 to solve for p, we have

4p+9r=75

4p+9(6.38)=75

4p+57.42= 75

4p=75-57.42

4p=17.58

p=17.58/4

p=4.395.

Therefore a box of pencil cost=$4.395

And a ream of paper cost=$6.38

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)