Match the area to each parallelogram and trapezoid.
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Area of first shape is 288, area of second shape is 45, area of third shape is 34.

Step-by-step explanation:

Area of first shape

A=bh

A=18*16

A=288

Second shape

A=bh

A=9*5

A=45

Third shape

A= 1/2 h(b1+b2)

A=1/24(12+5)

A=1/2*4(12+5)

A=1/2*4(17)

A=1/2*68

A=34

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180