HELP ASAP Larry deposits $36,000 into each of two savings accounts. Account I earns 2.6% interest compounded annually.
Account II earns 2.6% annual simple interest.
There are no additional deposits or withdrawals.
What is the sum of the balances of these accounts at the end of 9 years?

$89,779.37

$90,710.74

$90,958.61

$93,069.22

$90,958.61

Step-by-step explanation: I THINK

for 1st depositsx

p=$36000

r=2.6%

t=9years

compound amount =p(1+r/100)^t

=$36000(1+2.6/100)^9=$45355.37

for another deposit.

p=$36000

r=2.6%

t=9years

simple amount

=ptr/100=36000×2.6×9/100=$8424

total amount =$8424+$36000=$44424

the sum of the balances of these accounts at the end of 9 years=$44424+$45355.37=$89,779.37

  or  

step-by-step explanation:

if the four friends split the cost, p, of the pizza evenly, then each friend pays one-fourth of the cost of the pizza.

the expression is   or  

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.