A globe has a diameter of 12 inches. It fits inside a cube-shaped box that has a side length of 12 inches. What is the volume, rounded to the nearest hundredth of a cubic inch, of the space inside the box that is not taken up by
Volume of globe: V =
3
globe?
4
πη3
Since the diameter is 12, the radius is
4
Substitute r into the formula: V =
V=
lin²
Volume of box (square prism): V = Bh
B = s2 so B = (12)2 =
Substitute B and h into the formula: V = - (12)
V=
in3
Space not occupied by globe means the difference of the two volumes, so I
(circle correct operation) add/subtract/multiply divide.
Vbox - Vglobe
-904.32 =
in3

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

could you provide figure.

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)

you divide them and then you get the answer i took this class this year

step-by-step explanation: