Dadas las relaciones: \qquad m \angle ABD = 70^\circm∠ABD=70 ∘ m, angle, A, B, D, equals, 70, degrees \qquad m \angle CBD = 5x + 13^\circm∠CBD=5x+13 ∘ m, angle, C, B, D, equals, 5, x, plus, 13, degrees \qquad m \angle ABC = 3x + 33^\circm∠ABC=3x+33 ∘ m, angle, A, B, C, equals, 3, x, plus, 33, degrees Encuentra m\angle ABCm∠ABCm, angle, A, B, C:

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

6e14 is the answer.