They polynomial (3x-1)(x^2+2)-2x(x^2+x-1) can be written in the form ax^3+bx^2+cx+d, where a, b,c and d are constants. What are the values of a, b,c and d? Hint: Simplify the expression. Then look at each coefficient(constant) on your variables.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

(2,6)

step-by-step explanation:

cause i just did this and got the answer

you're welcome

30,40,50 is correct answer