A summer camp counselor wants to
calculate a length, x, in feet, across a pond
as represented in the sketch. Segments AC
and DE intersect at B, and AEB and CDB
have the same measure. What is the distance
across the pond? Round to the nearest
hundredth.

Answer is in the photo. I can only upload it to a file hosting service. link below! Good Luck!

https://cutt.ly/wzdvC7R

1600

Explanation: If angles E and D are the same with the lines intersecting at B, then that means that A and C are also the same, as the opposite angles formed at point B are also the same, so you have two similar triangles.

Similar triangles have proportional lengths. So we know length CD is 800 ft and its similar leg on the other side (AE) is unknown.

So we need to find two known lengths, one on the large and one on the small, that are similar.

BE is 1400 ft and BD is 700 ft. Those are you two known similar legs. So now we can use them in a proportion to find AE.

We will do the line ending at B over the line that doesn't include B.

Large triangle:

x

1400

​

Small triangle:

800

700

​

Set them up in a proportion:

x

1400

​

=

800

700

​

Solve for x:

⇒7x=11200

⇒x=1600 ft

Sorry if I get it wrong I tried my hardest

7

step-by-step explanation:

2.2°  

step-by-step explanation:

let θ = the angle of elevation.

tanθ =77/2020

tanθ = 0.038 12

      θ = tan⁻¹0.038 12

      θ = 2.2°