Write the equation of the line that passes through the points (2,1)(2,1) and (-8,-8)(−8,−8). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.

Step-by-step explanation:

m = (y2 - y1) / (x2 - x1)

It does NOT matter which point you make P1 and P2, the slope will be the same

I will take P1 = (-8, 4) and P2 = (-3, 7)

So m = 7 - 4 /(-3 - (-8)) = 3 / (-3 + 8) = 3/5

You can use the POINT-SLOPE formula to get the equation in the y = mx + b form and use any of the two points given...I will use P1 = (-8, 4)

POINT-SLOPE FORMULA:  y - y1 = m (x - x1)

y - 4 = 3/5 (x - (-8))

y - 4 =  3/5(x + 8)

y - 4 = 3/5(x) + 3/5(8)

y - 4 = 3/5(x) + 24/5

y = 3/5(x) + 24/5 + 4

Clean up the like terms on the RHS... 24/5 + 4 = 24/5 + 20/5 = 44/5

Final equation is y = 3/5(x) + 44/5

Hope this helps...

yes

step-by-step explanation:

give me the question

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so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse