Find the interior angle sum of this polygon.

Can someone help?

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Explanation:

See the diagram below. It shows there are 10 sides, so n = 10.

We'll plug this value of n into the formula below to find the sum of all ten interior angles

S = sum of interior angles

S = 180(n-2)

S = 180(10-2)

S = 180(8)

S = 1440 degrees

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A different approach:

Let's assume this polygon is a regular polygon. This means each angle is congruent to one another.

We have n = 10 sides, so each exterior angle is E = 360/n = 360/10 = 36 degrees.

Each interior angle adjacent to this 36 degree exterior angle is

180-E = 180-36 = 144 degrees

Since we have 10 equal angles of 144 degrees each, so overall the interior angles add to 10*144 = 1440 degrees

Side note: if this polygon is not a regular polygon, then this section does not apply. You would use the first method instead.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following