Mathematics, 08.03.2021 22:30 alemorachis49
Kishi draws a parabola with vertex at (6, 8) and x-intercepts at (2, 0) and (10, 0). Which is the equation of the parabola in standard form?
y=−(12)x2+6x−10
y=−(12)x2−6x−10
y=(12)x+6x−10
y=−(12)x−6x+10
Answers: 1
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Kishi draws a parabola with vertex at (6, 8) and x-intercepts at (2, 0) and (10, 0). Which is the eq...
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