the perimeter o DOG is 33. If DO = 10 and DG = 12, find the larger of the two segments into which the third side is divided by the angle bisector of ODG

The size of the larger of the two segments = 6

Step-by-step explanation:

Attached below is the triangle  ( DOG )

perimeter of Triangle = 33

DO = 10

DG = 12

OG = x

formula for perimeter = DO + DG + OG = 33

                                   = 10 + 12 + OG = 33

hence: OG = 33 - ( 10 + 12 ) = 33 - 22 = 11

third side ( x ) = 11

Finally determine the length of the larger of the two segments of side ( OG)

from the diagram below

  -------------------- ( 1 )  

where x' = 11 - y'

hence equation 1 becomes

10y' = 12x'

10y' = 12 ( 11 - y' )

10y' = 132 - 12y'

22y' = 132

∴ y' = 132 / 22 = 6

hence x' = 5

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.