(2x-5y)^2

Find the square using identity
Class 8

=4x^2−20xy+25y^2

Step-by-step explanation:

(2x−5y)^2

=(2x+−5y)(2x+−5y)

=(2x)(2x)+(2x)(−5y)+(−5y)(2x)+(−5y)(−5y)

=4x^2−10xy−10xy+25y^2

=4x^2−20xy+25y^2

Hope it helped!

(2x)^2- 2*(2x)*(5y)+(5y)^2= 4x^2-20xy+25y^2

Step-by-step explanation:

Identity- (a-b)^2= a^2-2ab+b^2

i don't even know man. edge inuity be messing with us. i had to ask a question too.