Given the definition of f(x)and g (x) below, find the value of (f g)(-1)

f(g(-1))  = 7

Step-by-step explanation:

Given the functions

f(x) = x^2 + 3x - 11

g(x) = 3x+6

f(g(x)) = f(3x+6)

f(3x+6) = ( 3x+6)² + 3( 3x+6) - 11

Substitute the value of x = -1

f(g(x)) = ( 3x+6)² + 3( 3x+6) - 11

f(g(-1)) = ( 3(-1)+6)² + 3( 3(-1)+6) - 11

f(g(-1)) = (-3+6)²+3(-3+6) - 11

f(g(-1))  = 3² + 3(3) - 11

f(g(-1)) = 9+9-11

f(g(-1)) =18 -11

f(g(-1))  = 7

sine

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)