Find a10 of the sequence 4, 28, 196, 1372 *Formula: a_n=a_1r^{n-1}a
n
​
=a
1
​
r
n−1

Step-by-step explanation:

Given sequence is: 4, 28, 196, 1372

28/4 = 7

196/28 = 7

1372/196 = 7

Since, the ratio of any two consecutive terms is same, so it is a geometric sequence.

Therefore,

Common ratio r = 7

First term a = 4

nth term of a geometric sequence is given as:

560

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