Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a radius of 11 feet and a height of 18 feet. Container B has a radius of 12 feet and a height of 14 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full. To the nearest tenth, what is the percent of Container A that is full after the pumping is complete?

The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

where r is the length of its radius

* In container A:

∵ r = 13 feet , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

is complete, divide the volume of water left in container A

by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol