Draw line segment AB - 7cm and bisect it using compass.​

(i) Draw a line segment AB = 7 cm.

(ii) With A as centre and radius more than half of AB, draw arcs, one on each side of AB.

(iii) With B as centre and same radius as before, draw arcs, cutting the previously drawn arcs at X and Y respectively.

(iv) Now join XY, meeting AB at O.

Thus, XY is the perpendicular bisector of AB.

Step-by-step explanation:

Hope it is helpful....

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: idk

step-by-step explanation: