Mathematics, 06.03.2021 02:10 sabrinamellis

Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the
length of RS and QR.

Answers: 2

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Given PQ = y, RS = 4y - 15, QR = 2 +6, and PS = 4a - 6, solve for the
length of RS and QR.