A TV remote control has keys for channels 0 through 9. ​a) If a key is selected at​ random, what is the probability that the key for channel 3 is​ pressed?
​b) If a key is selected at​ random, what is the probability that the key for an even number is​ pressed?
​c) If a key is selected at​ random, what is the probability that the key for a number more than 6 is​ pressed?

replication and blocking

step-by-step explanation:

the answer is a. 72. but i cant answer with less than 20 characters so here's some random text talking about it.

20/27

​​

step-by-step explanation:

1 simplify brackets

-\frac{8}{9}\times \frac{5}{6}−

​9

​

​8

​​ ×

​6

​

​5

​​

2 use this rule: \frac{a}{b}\times \frac{c}{d}=\frac{ac}{bd}

​b

​

​a

​​ ×

​d

​

​c

​​ =

​bd

​

​ac

​​

-\frac{8\times 5}{9\times 6}−

​9×6

​

​8×5

​​

3 simplify 8\times 58×5 to 4040

-\frac{40}{9\times 6}−

​9×6

​

​40

​​

4 simplify 9\times 69×6 to 5454

-\frac{40}{54}−

​54

​

​40

​​

5 simplify \frac{40}{54}

​54

​

​40

​​   to \frac{20}{27}

​27

​

​20

​​