A farmer is painting his silo. A typical can of paint covers 400 squared meters. How many cans of paint will the farmer need to buy in order to paint the entire exterior of the silo?

about 13 cans of paint

Step-by-step explanation:

To find how many cans the farmer needs to buy, you need to know the surface area of both the cone and cylinder.  

The way to find the SA of the cone would be area = 3.14 x r^2 + 3.14 x r x sqrt(r^2 + h^2).  

SA= 1976.0617791 m^2.

The way to find SA of the cylinder under the cone would be 3.14 x d x (d / 2 + h).

A = 3097.6103564 m^2

Then you have to add 1976.0617791+3097.6103564 which gives you 5,073.8. (5,073 being total surface area of the silo)

Next divide that by 400.

5,073.8/400 = 12.7

He would need to buy about 13 cans of paint to be able to paint the entire silo.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2