2 QUESTIONS. 1: Write an expression for the perimeter of this figure in simplest form.
a 3x^2+18
b3x+3
c3x+9
d3x+5

2nd question.
Find the area of the given triangle.
a 2x^2+5x+12
b x^2+5x+6
c 2x^2+10x+12

1.we know the perimeter of the triangle=x-3+x+6+x=3x+3

so,answer is (b)3x+3

2.area of the triangle=1/2*b*h

=1/2*x+2*2x+6=x+2*2x+6/2=2x^2+6x+4x+12/2=2x^2+10x+12/2=2(x^2+5x+6)/2=x^2+5x+6

so,answer is(b)x^2+5x+6

2 5/8 is the final answer! : )

answer

see attachment

explanation

the given function is

this function has y-intercept at

-4 and a slope of 2.

note that, the graph has a positive slope.

the graph that represents this function is the straight line that moves upward from left to right.

the graph touches the y-axis at -4.

the correct choice is the graph shown in the attachment.