A jewellery shop is having a sale a bracelet is now reduced to 420 pounds
this is 70% of the original price
A) workout the original price of the bracelet

a ring is now reduced to 840 pounds
this is a saving of 40% of the original price
b) workout the original price of the ring

a) £600

b) £1400

Step-by-step explanation:

a)

original price = x

reduced price = £420

reduced price is 70% of original price

Since the discounted price, £420, is 70% of the original price, x, then

70% of x = 420

0.7x = 420

x = 420/0.7

x = 600

£600

b)

original price = x

discounted price = £840

discount percentage = 40%

The original price is x, and x is 100% of the original price since 100% is the whole amount. The discount is 40% of the original price. 100% - 40% = 60%. That means the discounted price is 60% of the original price.

60% of x = 840

0.6x = 840

x = 840/0.6

x = 1400

£1400

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

1/2*qr*rs

step-by-step explanation: