Mathematics, 05.03.2021 05:50 andybiersack154

Solve for a (Hint: factor a and a?) abc2 + ab = ab + a²c
1
bc²+b
c²+b
a)
b)
d) None of the above
btc
btc2
C) C+
b+c

Answers: 2

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Solve for a (Hint: factor a and a?) abc2 + ab = ab + a²c
1
bc²+b
c²+b
a)