What is an equation of the line that passes through the point (-4,3) and is perpendicular to the line 4x – 5y 20?

y=-5x/4-2

Step-by-step explanation:

4x – 5y = 20

y = (4/5)x - 4

slope is 4/5

let new slope m:

(m)(4/5)=-1

m=-5/4

point slope form:

(y-3)/(x+4)=-5/4

y-3=-5x/4-5

y=-5x/4-2

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)