In ΔTUV, the measure of ∠V=90°, the measure of ∠U=70°, and UV = 9.6 feet. Find the length of TU to the nearest tenth of a foot.

​

28.1 feet

explaination

\cos U = \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{9.6}{x}

cosU=

hypotenuse

adjacent

​

=

x

9.6

​

\cos 70=\frac{9.6}{x}

cos70=

x

9.6

​

x\cos 70=9.6

xcos70=9.6

Cross multiply.

\frac{x\cos 70}{\cos 70}=\frac{9.6}{\cos 70}

cos70

xcos70

​

=

cos70

9.6

​

Divide each side by cos 70.

x=\frac{9.6}{\cos 70}=28.0685\approx 28.1\text{ feet}

x=

cos70

9.6

​

=28.0685≈28.1 feet

Type into calculator and roundto the nearest tenth of a foot.