An archer releases an arrow with an initial velocity of 20 feet per second at a height of 12 feet. The path the arrow takes can be modeled using the function f(x)=−16x2+20x+12, where f(x) represents the height, in feet, of the arrow and x represents the time the arrow travels in seconds. What is the maximum height, in feet, reached by the arrow? Round your answer to the nearest hundredth if necessary. Do not include units in your answer

18.25

Step-by-step explanation:

The arrow reaches its highest point at the y-value of the turning point. Thus, we need to find the maximum quadratic function.

-16x^2+20x+12

We know that the maximum( or minimum) of a parabola is reached at x= -b/(2a)= -20/ 2(-16)= 18.25

Showing that the object will reach a maximum height of 18.25 feet

it is b)

hope this : )

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: