A square has its length and width increased by two feet and four feet respectively so that it is now a rectangle. The perimeter of the new rectangle is eight feet less than twice the original perimeter. What was
the original perimeter? Show all work that leads to your answer. (Hint: Let x = the side length of the original
square). If you cannot do an algebraic approach, at least attempt it by guess and check

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9

step-by-step explanation: