Mathematics, 04.03.2021 19:40 rachael8304
What can be determined by looking at the polynomial f(x)=(x+3)(x−7)? A. The graph of the polynomial has a vertex at (3,−7). B. The graph of the polynomial has a vertex at (−3,7). C. The graph of the polynomial has zeros at (3,0) and (−7,0). D. The graph of the polynomial has zeros at(−3,0) and (7,0).
Answers: 2
Mathematics, 21.06.2019 19:50, Roshaan8039
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
What can be determined by looking at the polynomial f(x)=(x+3)(x−7)? A. The graph of the polynomial...
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