Find cosθ, tanθ, and cscθ, where θ is the angle shown in the figure. Give exact values, not decimal approximations.

Cos(θ) = 7/√58 ; Tan(θ) = 3/7 ; Csc(θ) = √58/3

Step-by-step explanation:

First, let's solve for the hypotenuse by using the Pythagorean Theorem.

a² + b² = c²

⇒ 7² + 3² = c²

⇒ 49 + 9 = c²

⇒ 58 = c²

⇒ √58 = c

Now that we know the hypotenuse is √58, we can solve for the trig ratios.

Cos(θ) = adjacent/hypotenuse = 7/√58

Tan(θ) = opposite/adjacent = 3/7

Csc(θ) = hypotenuse/opposite = √58/3

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step-by-step explanation:

mark brainliest!

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!