Jason purchased three different sizes of candy at the store. The medium candy was twice as expensive as the small candy. The large
candy was $5 more than the medium candy. He spent a total of $30 on
candy. Write and solve an equation to determine the cost of the small
candy.

$5

Step-by-step explanation:

Let the small candy be represented by x.

The medium candy was twice as expensive as the small candy. This will be: = 2×x = 2x

The large candy was $5 more than the medium candy. This will be: = 2x + 5

Since Jason spent a total of $30 on

candy, the cost of the small candy will be:

x + 2x + 2x + 5 = 30

5x + 5 = 30

5x = 30 - 5

5x = 25

x = 25/5

x= 5

The small candy cost $5

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584