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For f(x)=0.01(2) , find the average rate of change from x=3 to x=8.

Option b. 0.496

we know that

f(x)=0.01(2^{x})

The average rate of change is equal to

\frac{f(b)-f(a)}{b-a}

where

a=3

b=8

f(a)=f(3)=0.01(2^{3})=0.08

f(b)=f(8)=0.01(2^{8})=2.56

Substitute

\frac{2.56-0.08}{8-3}

\frac{2.48}{5}

0.496

i dont know i just need points

idk

step-by-step explanation: