![[x^2 - ln(2/x)]/[3x^2 + 2x]\\](/tpl/images/1166/9796/22a32.png)
![\frac{d}{dx}[x^2-ln(2/x)] =2x+\frac{1}{x}\\ \frac{d}{dx}[3x^2+2x]=6x+2\\\frac{2x+\frac{1}{x}}{6x+2}](/tpl/images/1166/9796/93325.png)
![\frac{d}{dx}[2x+\frac{1}{x}]=2-1/x^2\\\frac{d}{dx}[6x+2]=6\\\\](/tpl/images/1166/9796/970bb.png)
Use calculus to evaluate (lhopitals rule)
lim x>infinity x^2 - ln(2/x)/3x^2 + 2x...
Mathematics, 04.03.2021 05:50 2077087
Use calculus to evaluate (lhopitals rule)
lim x>infinity x^2 - ln(2/x)/3x^2 + 2x
Answers: 2
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