If EFGH is an isosceles trapezoid , EH = 4x-27, FG = x + 9 , EG = 3y + 19 and FH=11y-21, solve for x and y.

X = 12, Y = 5

Step-by-step explanation:

4x-27 = x+9

   +27      +27

4x = x + 36

-x     -x

3x = 36

3x/3 = 36/3

X = 12

3y + 19 = 11y - 21

     +21          +21

3y + 40 = 11y

-3y           -3y

40 = 8y

40/8 = 8y/8

Y = 5

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )