Barky's animal shelter has a total of 15 Chihuahuas and Yorkies. There are four
times as many Chihuahuas as Yorkies.
Using c for Chihuahuas and y for Yorkies,
determine which equation may be
used to represent this situation.
c=4+y
y=4+c
y=4c
c=4y

c = 4y

Step-by-step explanation:

Are there more, Chihuahuas or Yorkies?

Does  the word 'times' mean add, subtract, multiply or divide?

The way I look at it,  there are more Chihuahuas and 'times' means multiply.  Do you agree?

Therefore, I need to multiply 4 times the no. of Yorkies to get the no. of Chihuahuas

So,  c = 4y

Now, I don't see an equation in the list to choose from.  So, I don't know what to do from here.  I am guessing that c = 4y is what you want.

h df tyjgtyj ttd y ytkgfty ty

step-by-step explanation:

tyty jry j y yj yttj yhgtyj y ghyj ytthj

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.