A city bus collected $1,140 in fares on a given day. The regular fare is $1.50, and the reduced fare is $0.75. If 1,042 total fares were paid, which system of linear equations can be used to find x, the number of regular fares paid, and y, the number of reduced fares paid?

x + y = 1042

1.50x + 0.75y = 1140

Step-by-step explanation:

If there was a total of 1,042 fares paid then x + y would be equal to that because x is the number of regular fares paid and y is the number of reduced fares paid.

If there was a total of $1,140 made from the fares then we can use 1.50x + 0.75y. We put the 1.5 in front of the x because each fare paid costs $1.50, same with Y each reduced fare paid is $0.75. So both of those need to be added up to get $1,140.

d

step-by-step explanation:

d

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.