PLEASE HELP!! SHOW ALL WORK FOR BRAINLIEST Quadrilateral EFGH has vertices at E(10,4), F(16,4), G(16,10) and H(10,10). Based on the properties of the diagonals, is quadrilateral EFGH a rectangle, a rhombus, or a square?? Use the distance and slope formula to prove your conclusion. Must show all work please.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

6: 07 is your answer

step-by-step explanation:

it's undefined because anything multiplied by 0 is 0. that said, 7 days is 168 hours

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6